Fluid Mechanics · Unit 1 · Lesson 13 of 13

Where Do Mechanical Engineers Use Fluid Mechanics?

Applications in mechanical engineering 8 min

Curiosity question

Count the fluids working inside one car: fuel, air, coolant, brake fluid, engine oil, refrigerant. Why does a mechanical engineer need to understand every one of them?

1. Real-World Problem

A family's water pump runs every morning to fill the rooftop tank. How much power does it really need, how much electricity does it use, and why is the motor rated higher than the power the water receives?

2. Predict

Make your guess before you try the experiment. You will see the answer after the next step.

Predict

A pump lifts water to a tank. If the tank is moved twice as high and the flow stays the same, the power given to the water:

3. Experiment

Switch between the Car, Power Plant and Factory scenes and open each hotspot to see what the fluid does and which subject goes deeper.

Then use the Pump Power calculator: lift 1 L/s through 20 m with a 60% pump and an 85% motor, and see where the power goes. Add a tariff to see the monthly cost, and a better pump to see its payback.

4. Understand

ApplicationWhat fluid mechanics answersSubject that goes deeper
Pumps and compressorsHow much power to move a fluid at a given flow and heightFluid Machinery
Hydraulic and steam turbinesHow much power can be taken out of a moving fluidFluid Machinery, Power Plant Engineering
IC enginesHow air and fuel flow in, mix and leave as exhaustApplied Thermodynamics And IC Engines
Cooling systems (radiators, heat exchangers)How fast coolant must flow to carry heat awayHeat Transfer
Refrigeration and air conditioningHow refrigerant and air move through coils and ductsRefrigeration And Air Conditioning
Hydraulic machines (brakes, presses, excavators)How liquid pressure multiplies forceFluid Machinery
Lubrication of bearings and gearsHow an oil film keeps metal surfaces apartMachine Design
Vehicle and aircraft aerodynamicsHow much drag and lift the shape createsAutomobile Engineering, Computational Fluid Dynamics
Piping networks in plants and buildingsHow much pressure is lost through pipes and fittingsFluid Mechanics (later units)
Wind turbinesHow much power the wind can deliverRenewable Energy Systems

Three different powers appear in every pump installation. Hydraulic power is what the water actually receives. Shaft power is what the motor must deliver to the pump shaft; it is larger because the pump loses some energy to friction and leakage. Electrical input power is what the motor draws from the supply; it is larger again because the motor has its own losses.

5. Derive

Step 1. Lifting a mass m through a height H needs energy mgH.

Step 2. Per second, the pump lifts a mass ṁ = ρQ, so the power given to the water is:

P_{hyd} = \rho\, g\, Q\, H

P_hyd is hydraulic power (W), ρ density (kg/m³), g = 9.81 m/s², Q volume flow rate (m³/s), H the height the water is lifted (m).

Step 3. The pump has efficiency η_pump, so the shaft must supply more:

P_{shaft} = \frac{P_{hyd}}{\eta_{pump}}

Step 4. The motor has efficiency η_motor, so the electrical input is larger again:

P_{elec} = \frac{P_{shaft}}{\eta_{motor}} = \frac{\rho\, g\, Q\, H}{\eta_{pump}\,\eta_{motor}}

6. Calculate

Lift 1 L/s (0.001 m³/s) to a tank 20 m up, pump efficiency 60%, motor efficiency 85%.

  • Hydraulic power: 1000 × 9.81 × 0.001 × 20 = 196 W.
  • Pump shaft power: 196 ÷ 0.60 = 327 W. This is the idealised shaft power the motor must deliver to the pump.
  • Electrical input: 327 ÷ 0.85 = 385 W.
  • Running 1 hour a day: 0.385 kWh per day, about 11.5 kWh in a 30-day month. At an example tariff of ₹8 per kWh, about ₹92 a month.

7. Apply

  • The motor pump that fills your overhead tank: exactly the formula above. Home pumps of 0.5 hp (373 W shaft output, using the 746 W mechanical horsepower on pump nameplates) are common because they cover about this much lift and flow.
  • Hydraulic brakes in every car and two-wheeler with disc brakes.
  • Thermal power plants, where water and steam carry the energy from fuel to electricity.
  • Cars and trains shaped with wind tunnels and CFD to cut fuel use.
  • Bearings in every engine and turbine, carried on a thin oil film.

8. Validate

In the Pump Power calculator enter Q = 1 L/s, H = 20 m, 60% and 85%: it must show 196 W, 327 W and 385 W. Check against reality: the 327 W shaft power fits within a 0.5 hp (373 W, mechanical horsepower) motor's rated output, which is what many homes use for this job. Where the formula underestimates: real pipes add friction losses, so the pump must work against a total head larger than the height lifted (later units).

Easy To Mix Up

  • Hydraulic power, shaft power and electrical input are three different numbers. The motor's nameplate rating (kW or hp) is its shaft output, not its electrical input.
  • Pump and motor efficiencies are never 100%, so each stage needs more power than the one after it.
  • Fluid mechanics is not only for "fluid" machines. Gears, bearings and engines all depend on it through lubrication and cooling.

9. Quiz

Four quick questions: a concept, a calculation and an interpretation. Each answer comes with an explanation. Score 3 or more to mark this lesson completed.

Check Your Understanding

Four questions: a concept, a calculation and an interpretation. Every answer comes with an explanation. Score 3 of 4 to mark the lesson completed.

Up next

Put it all together in the Unit 1 Engineering Project. Then Unit 2 starts with the properties that make each fluid different: density, viscosity and surface tension.

Open the Unit 1 Engineering Project →

Read More

  • Cengel and Cimbala, "Mass, Bernoulli and Energy Equations" (pump and motor efficiency) and "Turbomachinery"; Bansal, "Centrifugal Pumps".
  • NPTEL, Introduction to Fluid Mechanics (Prof. Suman Chakraborty, IIT Kharagpur): Weeks 9 to 11.