Fluid Mechanics · Unit 1 · Lesson 13 of 13
Where Do Mechanical Engineers Use Fluid Mechanics?
Applications in mechanical engineering 8 min
Count the fluids working inside one car: fuel, air, coolant, brake fluid, engine oil, refrigerant. Why does a mechanical engineer need to understand every one of them?
1. Real-World Problem
A family's water pump runs every morning to fill the rooftop tank. How much power does it really need, how much electricity does it use, and why is the motor rated higher than the power the water receives?
2. Predict
Make your guess before you try the experiment. You will see the answer after the next step.
Predict
3. Experiment
Switch between the Car, Power Plant and Factory scenes and open each hotspot to see what the fluid does and which subject goes deeper.
Then use the Pump Power calculator: lift 1 L/s through 20 m with a 60% pump and an 85% motor, and see where the power goes. Add a tariff to see the monthly cost, and a better pump to see its payback.
4. Understand
| Application | What fluid mechanics answers | Subject that goes deeper |
|---|---|---|
| Pumps and compressors | How much power to move a fluid at a given flow and height | Fluid Machinery |
| Hydraulic and steam turbines | How much power can be taken out of a moving fluid | Fluid Machinery, Power Plant Engineering |
| IC engines | How air and fuel flow in, mix and leave as exhaust | Applied Thermodynamics And IC Engines |
| Cooling systems (radiators, heat exchangers) | How fast coolant must flow to carry heat away | Heat Transfer |
| Refrigeration and air conditioning | How refrigerant and air move through coils and ducts | Refrigeration And Air Conditioning |
| Hydraulic machines (brakes, presses, excavators) | How liquid pressure multiplies force | Fluid Machinery |
| Lubrication of bearings and gears | How an oil film keeps metal surfaces apart | Machine Design |
| Vehicle and aircraft aerodynamics | How much drag and lift the shape creates | Automobile Engineering, Computational Fluid Dynamics |
| Piping networks in plants and buildings | How much pressure is lost through pipes and fittings | Fluid Mechanics (later units) |
| Wind turbines | How much power the wind can deliver | Renewable Energy Systems |
Three different powers appear in every pump installation. Hydraulic power is what the water actually receives. Shaft power is what the motor must deliver to the pump shaft; it is larger because the pump loses some energy to friction and leakage. Electrical input power is what the motor draws from the supply; it is larger again because the motor has its own losses.
5. Derive
Step 1. Lifting a mass m through a height H needs energy mgH.
Step 2. Per second, the pump lifts a mass ṁ = ρQ, so the power given to the water is:
P_{hyd} = \rho\, g\, Q\, HP_hyd is hydraulic power (W), ρ density (kg/m³), g = 9.81 m/s², Q volume flow rate (m³/s), H the height the water is lifted (m).
Step 3. The pump has efficiency η_pump, so the shaft must supply more:
P_{shaft} = \frac{P_{hyd}}{\eta_{pump}}Step 4. The motor has efficiency η_motor, so the electrical input is larger again:
P_{elec} = \frac{P_{shaft}}{\eta_{motor}} = \frac{\rho\, g\, Q\, H}{\eta_{pump}\,\eta_{motor}}6. Calculate
Lift 1 L/s (0.001 m³/s) to a tank 20 m up, pump efficiency 60%, motor efficiency 85%.
- Hydraulic power: 1000 × 9.81 × 0.001 × 20 = 196 W.
- Pump shaft power: 196 ÷ 0.60 = 327 W. This is the idealised shaft power the motor must deliver to the pump.
- Electrical input: 327 ÷ 0.85 = 385 W.
- Running 1 hour a day: 0.385 kWh per day, about 11.5 kWh in a 30-day month. At an example tariff of ₹8 per kWh, about ₹92 a month.
7. Apply
- The motor pump that fills your overhead tank: exactly the formula above. Home pumps of 0.5 hp (373 W shaft output, using the 746 W mechanical horsepower on pump nameplates) are common because they cover about this much lift and flow.
- Hydraulic brakes in every car and two-wheeler with disc brakes.
- Thermal power plants, where water and steam carry the energy from fuel to electricity.
- Cars and trains shaped with wind tunnels and CFD to cut fuel use.
- Bearings in every engine and turbine, carried on a thin oil film.
8. Validate
In the Pump Power calculator enter Q = 1 L/s, H = 20 m, 60% and 85%: it must show 196 W, 327 W and 385 W. Check against reality: the 327 W shaft power fits within a 0.5 hp (373 W, mechanical horsepower) motor's rated output, which is what many homes use for this job. Where the formula underestimates: real pipes add friction losses, so the pump must work against a total head larger than the height lifted (later units).
Easy To Mix Up
- Hydraulic power, shaft power and electrical input are three different numbers. The motor's nameplate rating (kW or hp) is its shaft output, not its electrical input.
- Pump and motor efficiencies are never 100%, so each stage needs more power than the one after it.
- Fluid mechanics is not only for "fluid" machines. Gears, bearings and engines all depend on it through lubrication and cooling.
9. Quiz
Four quick questions: a concept, a calculation and an interpretation. Each answer comes with an explanation. Score 3 or more to mark this lesson completed.
Check Your Understanding
Four questions: a concept, a calculation and an interpretation. Every answer comes with an explanation. Score 3 of 4 to mark the lesson completed.
Put it all together in the Unit 1 Engineering Project. Then Unit 2 starts with the properties that make each fluid different: density, viscosity and surface tension.
Open the Unit 1 Engineering Project →Read More
- Cengel and Cimbala, "Mass, Bernoulli and Energy Equations" (pump and motor efficiency) and "Turbomachinery"; Bansal, "Centrifugal Pumps".
- NPTEL, Introduction to Fluid Mechanics (Prof. Suman Chakraborty, IIT Kharagpur): Weeks 9 to 11.